Sets: Difference between revisions
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<table border="1" cellpadding="5" cellspacing="0" rules="none" summary=""> | <table id="symmetric_difference" border="1" cellpadding="5" cellspacing="0" rules="none" summary=""> | ||
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<table border="1" cellpadding="5" cellspacing="0" rules="none" summary=""> | <table id="subset" border="1" cellpadding="5" cellspacing="0" rules="none" summary=""> | ||
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<table border="1" cellpadding="5" cellspacing="0" rules="none" summary=""> | <table id="superset" border="1" cellpadding="5" cellspacing="0" rules="none" summary=""> | ||
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Latest revision as of 14:31, 9 September 2022
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L is a scalar or one-element vector. | ||||
R is a scalar or one-element vector. | ||||
Z is the vector result equivalent to (L~R),R~L. |
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L is a scalar or one-element vector. | ||||
R is a scalar or one-element vector. | ||||
Z is the Boolean scalar result equivalent to ∧/L∊R as well as R⊇L. |
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L is a scalar or one-element vector. | ||||
R is a scalar or one-element vector. | ||||
Z is the Boolean scalar result equivalent to ∧/R∊L as well as R⊆L. |
These functions behave differently when invoked via the Multiset Operator which takes into account multiplicities.
For example,
'miasma'§'sis' mama 'miasma'§⍦'sis' ⍝ Using the Multiset form mamas 'immiss'⊆'mississippi' 1 'immiss'⊆⍦'mississippi' ⍝ Using the Multiset form 0 ⍝ because the # m's doesn't match