CombinatorialCase012: Difference between revisions
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* <apll>M</apll> unlabeled balls (0), <apll>N</apll> labeled boxes (1), at least one ball per box (2) | * <apll>M</apll> unlabeled balls (0), <apll>N</apll> labeled boxes (1), at least one ball per box (2) | ||
* Not <apll>⎕IO</apll>-sensitive | * Not <apll>⎕IO</apll>-sensitive | ||
* Allows Lexicographic order | |||
* Counted result is an integer scalar | * Counted result is an integer scalar | ||
* Generated result is an integer matrix. | * Generated result is an integer matrix. | ||
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<pre> | <pre> | ||
12 1‼5 3 ⍝ Compositions in unspecified order | |||
1 1 3 | |||
2 1 2 | |||
1 2 2 | |||
3 1 1 | |||
2 2 1 | |||
1 3 1 | |||
12 2‼5 3 ⍝ Compositions in Lexicographic order | |||
1 1 3 | 1 1 3 | ||
1 2 2 | 1 2 2 | ||
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2 2 1 | 2 2 1 | ||
3 1 1 | 3 1 1 | ||
12 3‼5 3 ⍝ Gray Code order not implemented as yet | |||
NONCE ERROR | |||
12 3‼5 3 | |||
∧ | |||
⍝ Compositions of M into N parts | ⍝ Compositions of M into N parts | ||
⍝ Unlabeled balls, labeled boxes, ≥1 # Balls per Box | ⍝ Unlabeled balls, labeled boxes, ≥1 # Balls per Box | ||
12 2‼5 5 | |||
1 1 1 1 1 | 1 1 1 1 1 | ||
12 2‼5 4 | |||
1 1 1 2 | 1 1 1 2 | ||
1 1 2 1 | 1 1 2 1 | ||
1 2 1 1 | 1 2 1 1 | ||
2 1 1 1 | 2 1 1 1 | ||
12 2‼5 3 | |||
1 1 3 | 1 1 3 | ||
1 2 2 | 1 2 2 | ||
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2 2 1 | 2 2 1 | ||
3 1 1 | 3 1 1 | ||
12 2‼5 2 | |||
1 4 | 1 4 | ||
2 3 | 2 3 | ||
3 2 | 3 2 | ||
4 1 | 4 1 | ||
12 2‼5 1 | |||
5 | 5 | ||
</pre> | </pre> |
Revision as of 16:07, 21 October 2017
This case produces Compositions of the number M into N parts. A composition is a way of representing a number as the sum of all positive integers, in this case it’s a way of representing M as the sum of N positive integers. It can also be thought of as a Partition of M into N Ordered Parts.
- M unlabeled balls (0), N labeled boxes (1), at least one ball per box (2)
- Not ⎕IO-sensitive
- Allows Lexicographic order
- Counted result is an integer scalar
- Generated result is an integer matrix.
The count for this function is (M-N)!M-1.
For example:
If we have 5 unlabeled balls (●●●●●) and 3 labeled boxes (123) with at least one ball per box, there are 6 (↔ (5-3)!5-1) ways to meet these criteria:
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The diagram above corresponds to
12 1‼5 3 ⍝ Compositions in unspecified order 1 1 3 2 1 2 1 2 2 3 1 1 2 2 1 1 3 1 12 2‼5 3 ⍝ Compositions in Lexicographic order 1 1 3 1 2 2 1 3 1 2 1 2 2 2 1 3 1 1 12 3‼5 3 ⍝ Gray Code order not implemented as yet NONCE ERROR 12 3‼5 3 ∧ ⍝ Compositions of M into N parts ⍝ Unlabeled balls, labeled boxes, ≥1 # Balls per Box 12 2‼5 5 1 1 1 1 1 12 2‼5 4 1 1 1 2 1 1 2 1 1 2 1 1 2 1 1 1 12 2‼5 3 1 1 3 1 2 2 1 3 1 2 1 2 2 2 1 3 1 1 12 2‼5 2 1 4 2 3 3 2 4 1 12 2‼5 1 5
In general, because the counts of both compositions (012) and combinations (010) is a binomial coefficient, there might be a mapping between the two, and indeed there is, as seen by the following identities:
010 1‼M N ↔ +\0 ¯1↓012 1‼⍠1 N M+1 012 1‼M N ↔ ¯2-\(010 1‼⍠1 N M-1),M
where ‼⍠1 uses the Variant operator ⍠ to evaluate ‼ in origin 1.