CombinatorialCase001: Difference between revisions

From NARS2000
Jump to navigationJump to search
mNo edit summary
No edit summary
 
Line 6: Line 6:
* Generated result is a nested vector of integer vectors.
* Generated result is a nested vector of integer vectors.


The count for this function is <apll>(M+N)PN N</apll> where <apll>M PN N</apll> calculates the number of [https://en.wikipedia.org/wiki/Partition_(number_theory) Partitions] of the number <apll>M</apll> into exactly <apll>N</apll> parts.
The count for this function is <apll>(M+N)PN N</apll> where <apll>M PN N</apll> calculates the number of [https://en.wikipedia.org/wiki/Partition_(number_theory)#Restricted_part_size_or_number_of_parts Partitions] of the number <apll>M</apll> into exactly <apll>N</apll> parts.


For example:
For example:

Latest revision as of 18:49, 19 June 2017

This case produces the Partitions of the number M into at most N parts.

  • M unlabeled balls (0), N unlabeled boxes (0), any # of balls per box (1)
  • Not ⎕IO-sensitive
  • Counted result is an integer scalar
  • Generated result is a nested vector of integer vectors.

The count for this function is (M+N)PN N where M PN N calculates the number of Partitions of the number M into exactly N parts.

For example:

If we have 6 unlabeled balls (●●●●●●) and 3 unlabeled boxes with any # of balls per box, there are 7 (↔ (6+3)PN 3) ways to meet these criteria:






       
     
 




 
 
 
 
 
   
     
 
 



 
 
 
 

   
     
 
 



 
 
 
 
 
 
 
 
 
 
     
 
 
 


 
 
 


   
     
 
 
 


 
 
 
 

 
 
 
 
 
     
 
 
 
 

 
 
 
 

 
 
 
 

     

The diagram above corresponds to the nested array

      ⍪001 1‼6 3
 6
 5 1
 4 2
 4 1 1
 3 3
 3 2 1
 2 2 2
      ⍝ Partitions of M into at most N parts
      ⍝ Unlabeled balls & boxes, any # Balls per Box
      ⍪001 1‼5 5
 5
 4 1
 3 2
 3 1 1
 2 2 1
 2 1 1 1
 1 1 1 1 1
      ⍪001 1‼5 4
 5
 4 1
 3 2
 3 1 1
 2 2 1
 2 1 1 1
      ⍪001 1‼5 3
 5
 4 1
 3 2
 3 1 1
 2 2 1
      ⍪001 1‼5 2
 5
 4 1
 3 2
      ⍪001 1‼5 1
 5

Identities

As shown in Wikipedia, (M+N)PN N ↔ +/M PN¨0..N.

Because partitions of M into N non-negative parts (001) is the same as partitions of M+N into N positive parts (002), these cases are related by the following identity:

001 1‼M N ↔ (⊂[⎕IO+1] ¯1+002 1‼(M+N) N)~¨0