CombinatorialCase012: Difference between revisions
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This case produces '''Compositions of the number <apll> | This case produces '''Compositions of the number <apll>M</apll> into <apll>N</apll> parts'''. A composition is a way of representing a number as the sum of all positive integers, in this case it’s a way of representing <apll>M</apll> as the sum of <apll>N</apll> positive integers. It can also be thought of as a partition of <apll>M</apll> into <apll>N</apll> ordered parts. | ||
* <apll> | * <apll>M</apll> unlabeled balls (0), <apll>N</apll> labeled boxes (1), at least one ball per box (2) | ||
* Not <apll>⎕IO</apll>-sensitive | * Not <apll>⎕IO</apll>-sensitive | ||
* Counted result is an integer scalar | * Counted result is an integer scalar | ||
* Generated result is an integer matrix. | * Generated result is an integer matrix. | ||
The count for this function is <apll>( | The count for this function is <apll>(M-N)!M-1</apll>. | ||
For example: | For example: | ||
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2 2 1 | 2 2 1 | ||
3 1 1 | 3 1 1 | ||
⍝ Compositions of | ⍝ Compositions of M into N parts | ||
⍝ Unlabeled balls, labeled boxes, ≥1 # Balls per Box | ⍝ Unlabeled balls, labeled boxes, ≥1 # Balls per Box | ||
012 1‼5 5 | 012 1‼5 5 | ||
Line 113: | Line 113: | ||
<pre> | <pre> | ||
010 | 010 1‼M N ↔ +\0 ¯1↓012 1‼⍠1 N M+1 | ||
012 | 012 1‼M N ↔ ¯2-\(010 1‼⍠1 N M-1),M | ||
</pre> | </pre> | ||
where <apll>‼⍠1</apll> uses the Variant operator <apll>⍠</apll> to evaluate <apll>‼</apll> in origin <apll>1</apll>. | where <apll>‼⍠1</apll> uses the Variant operator <apll>⍠</apll> to evaluate <apll>‼</apll> in origin <apll>1</apll>. |
Revision as of 17:10, 14 May 2017
This case produces Compositions of the number M into N parts. A composition is a way of representing a number as the sum of all positive integers, in this case it’s a way of representing M as the sum of N positive integers. It can also be thought of as a partition of M into N ordered parts.
- M unlabeled balls (0), N labeled boxes (1), at least one ball per box (2)
- Not ⎕IO-sensitive
- Counted result is an integer scalar
- Generated result is an integer matrix.
The count for this function is (M-N)!M-1.
For example:
If we have 5 unlabeled balls (●●●●●) and 3 labeled boxes (123) with at least one ball per box, there are 6 (↔ (5-3)!5-1) ways to meet these criteria:
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The diagram above corresponds to
012 1‼5 3 1 1 3 1 2 2 1 3 1 2 1 2 2 2 1 3 1 1 ⍝ Compositions of M into N parts ⍝ Unlabeled balls, labeled boxes, ≥1 # Balls per Box 012 1‼5 5 1 1 1 1 1 012 1‼5 4 1 1 1 2 1 1 2 1 1 2 1 1 2 1 1 1 012 1‼5 3 1 1 3 1 2 2 1 3 1 2 1 2 2 2 1 3 1 1 012 1‼5 2 1 4 2 3 3 2 4 1 012 1‼5 1 5
In general, because the counts of both compositions (012) and combinations (010) is a binomial coefficient, there might be a mapping between the two, and indeed there is, as seen by the following identities:
010 1‼M N ↔ +\0 ¯1↓012 1‼⍠1 N M+1 012 1‼M N ↔ ¯2-\(010 1‼⍠1 N M-1),M
where ‼⍠1 uses the Variant operator ⍠ to evaluate ‼ in origin 1.